"p varies directly as q and the square of r and inversely as s "
-----> p = k(qr^2/s) , where k is a constant
find k if p=40 q=5 r=4 s=6
you are given the values of the 4 variables, sub them into the above equation to solve for k
then rewrite the equation.
let me know what you get for the first one, to make sure you are doing it correctly.
p varies directly as q and the square of r and inversely as s
write the equation of the relation
find k if p=40 q=5 r=4 s=6
find p when q=8 r=6 and s=9
find s when p=10 q=5 r=2
6 answers
40=k*(5*4^2)/6
40*6=5*16*k
240=80*k
k=240/80
k=3.
p=(3qr^2)/s
40*6=5*16*k
240=80*k
k=240/80
k=3.
p=(3qr^2)/s
Can you please check my answers? Thanxs! 40=k*(5*4^2)/6
40*6=5*16*k
240=80*k
k=240/80
k=3.
p=(3qr^2)/s
40*6=5*16*k
240=80*k
k=240/80
k=3.
p=(3qr^2)/s
The quality R varies directly as the square of S and inversely proportional as the root of T
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Is that the answer
1 answer