P, q and r are points on the same horizontal plane. The bearing of q from p is 150 and the bearing of r from q is 060 if line p and q is equal to 5 and line q and r is 3 find the bearing of r from p, correct to the nearest degree. (Waec)

2 answers

Some one should help me
According to your description I made triangle PQR ,
so that PQ = 5, QR = 3 and with basic geometry found angle Q = 90°
using the tangent ratio,
tan QPR = 3/5
so angle P of the triangle = 30.96°

let me know what your final answer is