P(E)=.4, P(F)=.5 and P(E[intersect]F)=.1 , Calculate P(F[suchthat]E)=?
Using conditional probability, I got .2 as the answer, right?
Is the answer the same for P(EsuchthatF)?
2 answers
wouldn't it be .25? check my thinking.
Bob Pursley - Thank-you! I figured out how you got .25