P(E)=.4, P(F)=.5 and P(E[intersect]F)=.1 , Calculate P(F[suchthat]E)=?

Using conditional probability, I got .2 as the answer, right?

Is the answer the same for P(EsuchthatF)?

2 answers

wouldn't it be .25? check my thinking.
Bob Pursley - Thank-you! I figured out how you got .25