Oxygen gas has a Henry's law constant of 1.66*10^-6 M/mm Hg at 40 degree C when dissolving in water. If the total pressure of gass (O2 gas plus water vapor) over water is 1.0 atm, what is the concentration of O2 in the water in grams per milliliter? Pressure of the water vapor at 40 degree C = 55.3 torrs.

Answer 1

C = k*p
C = 1.66E-6M/mm x mm
(760 mm - 55.3 = 704.7)
C = 1.66E-6 M/mm*704.7 mm = ? M
Convert that to grams/L and to g/mL.

Answer 2

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