Asked by Josh

at 298 k, the Henry's law constant for oxygen is 0.00130 M/atm. Air is 21.0% oxygen. at 298 k, what is the solubility of oxygen in water exposed to air at 1.00 atm?
Answered by DrBob222
21.0% oxygen is 21 mole percent.
0.00130 M/atm x 0.21 atm = ??M
Answered by t
2.73 x 10^-4
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