Question
If a car accelerates at a constant rate of -5.60m/s^2 while braking, the velocity changes from +12.5m/s to +3.30m/s.
a) determine the amount of time it takes to do this.
b) determine how far the car travels during the time.
a) determine the amount of time it takes to do this.
b) determine how far the car travels during the time.
Answers
R_scott
a) (velocity change) / acceleration = time
... (3.30 m/s / 12.5 m/s) / (-5.60 m/s^2) = t
b) distance = average velocity * time
... d = [(12.5 m/s + 3.30 m/s) / 2] * t
... (3.30 m/s / 12.5 m/s) / (-5.60 m/s^2) = t
b) distance = average velocity * time
... d = [(12.5 m/s + 3.30 m/s) / 2] * t