Over July 16, 1882, a massive thunderstorm over Dubuque, Iowa, produced huge hailstones. The diameter of some of the hailstones was 17 inches. Ice weighs about 0.033 lb/in^3. What was the approximate weight of these hailstones to the nearest pound?

Question

The book has the answer of 85 lbs .
I need help on trying to solve it , please help ???

Answer 1

r = 8.5
Vol = (4/3)pi(r^3)
= (4/3)pi(8.5)^3)
= 2572.44 inches^3

mass = 2572.44(.033) = 84.89 or 85 lbs

Answer 2

Weight = density x volume

Just multiply the density (in lb/in^3) by the hailstone volume in cubic inches.

You will need to remember that volume of a sphere of diameter D is
V = (pi/6)D^3

Answer 3

just cry

Answer 4

the "Circumference" of the hailstone was 17" not the Diameter. No wonder your answer was catastrophic (85lb.)! This question was unanswered so long -- it's melted by now.