Asked by Ethan
Only two horizontal forces act on a 9.1 kg body. One force is 5.3 N, acting due east, and the other is 1.6 N, acting 56° north of west. What is the magnitude of the body's acceleration?
Answers
Answered by
bobpursley
figure the acceleration in each direction.
a1=5.3/9.1 E
a2=1.6/9.1 in direction 53g NofW
You know the angle between, 180-56=124
Law of cosines:
magnitude acceleration^2=a1^2+a2^2-a1*a2*cos124
a1=5.3/9.1 E
a2=1.6/9.1 in direction 53g NofW
You know the angle between, 180-56=124
Law of cosines:
magnitude acceleration^2=a1^2+a2^2-a1*a2*cos124
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