35. To find the true mass of water delivered in A, we can use the given density of water at 19.0°C (0.9984 g/mL) and the apparent burette reading (10.05 mL).
True mass = (apparent burette reading) × (density of water)
True mass = 10.05 mL × 0.9984 g/mL = 10.03442 g
The closest value in the options is 10.03 g, so the answer is A) 10.03 g.
36. We do the same for B, using the burette reading of 20.04 mL.
True mass = 20.04 mL × 0.9984 g/mL = 20.011456 g
The closest value from the options is 20.12 g, so the answer is A) 20.12 g.
37. We carry out the same calculation for C, with the burette reading of 30.08 mL.
True mass = 30.08 mL × 0.9984 g/mL = 30.038848 g
The closest value from the options is 30.09 g, so the answer is D) 30.09 g.
38. For D, we use the burette reading of 40.07 mL.
True mass = 40.07 mL × 0.9984 g/mL = 40.066088 g
The closest value from the options is 40.07 g, so the answer is C) 40.07 g.
39. To find the true volume of water delivered in A, we can use the true mass of water and the density of water.
True volume = (true mass) / (density of water)
True volume = 10.03 g / 0.9984 g/mL = 10.044088 mL
The closest value to 10.044088 mL is 10.04 mL, so the answer is C) 10.04 mL.
40. We do the same for B.
True volume = 20.12 g / 0.9984 g/mL = 20.144289 mL
The closest value from the options is 20.14 mL, so the answer is B) 20.14 mL.
41. For D, we use the same calculation.
True volume = 40.07 g / 0.9984 g/mL = 40.110442 mL
The closest value from the options is 40.11 mL, so the answer is A) 40.11 mL.
42. Using the same calculation for E:
True volume = 49.83 g / 0.9984 g/mL = 49.941764 mL
The closest value to 49.941764 mL is 49.94 mL, so the answer is D) 49.94 mL.
43. To find the correction volume of water delivered in C, we can use the true volume and the apparent burette reading.
Correction volume = (true volume) - (apparent burette reading)
Correction volume = 30.038848 mL - 30.08 mL = -0.041152 mL
The closest value from the options is -0.04 mL, so the answer is D) -0.04 mL.
44. For D, we have already calculated the true volume in question 41.
True volume of water delivered in D = 40.11 mL, so the answer is A) 0.11 mL.
One student calibrated a 50-mL burette by using the mass of water delivered. The student used an analytical balance which was previously calibrated
by STEEL (density = 7.8 g/mL). During calibration, the temperature of water was found to be 19.0oC. The density of water at this temperature is
0.9984 g/mL. The results of the calibration by the student is shown in the table below:
A B C D E
Apparent burette reading, mL 10.05 20.04 30.08 40.07 49.98
Weight H2O delivered, g 10.03 20.09 30.05 40.02 49.83
35. What is the true mass of water delivered in A?
A) 10.03
B) 10.04
C) 10.05
D) 10.06
E) 10.07
36. What is the true mass of water delivered in B?
A) 20.12
B) 20.13
C) 20.14
D) 20.15
E) 20.16
37. What is the true mass of water delivered in C?
A) 30.13
B) 30.11
C) 30.10
D) 30.09
E) 30.08
38. What is the true mass of water delivered in D?
A) 40.09
B) 40.08
C) 40.07
D) 40.06
E) 40.05
39. What is the true volume of water delivered in A?
A) 10.00
B) 10.02
C) 10.04
D) 10.06
E) 10.08
40. What is the true volume of water delivered in B?
A) 20.12
B) 20.14
C) 20.16
D) 20.18
E) 20.20
41. What is the true volume of water delivered in D?
A) 40.11
B) 40.12
C) 40.13
D) 40.14
E) 40.15
42. What is the true volume of water delivered in E?
A) 50.00
B) 49.98
C) 49.96
D) 49.94
E) 49.92
43. What is the correction volume of water delivered in C?
A) 0.04
B) 0.08
C) 0.00
D) -0.04
E) -0.08
44. What is the true volume of water delivered in D?
A) 0.11
B) 0.12
C) 0.13
D) 0.14
E) 0.15
1 answer