One solution contains 25% as much water as alcohol and another solution contains 5 times as much water as alcohol. How many gallons of each solution must be mixed in order to obtain 7 gallons of the new solution which contains as much water as alcohol?
Please help. I don't know how to solve this problem.
2 answers
Anne/Jeysi/Ben -- please use the same name for your posts.
call the solutions A and B.
If there are x gal of A, then there are 7-x gal of B.
So, if we keep track of the alcohol amounts, we have
4/5 x + 1/6 (7-x) = 1/2 (7)
Now just solve for x, the amount of solution A.
If there are x gal of A, then there are 7-x gal of B.
So, if we keep track of the alcohol amounts, we have
4/5 x + 1/6 (7-x) = 1/2 (7)
Now just solve for x, the amount of solution A.
3 answers