As usual, this is not hard if you understand what is going on.
The amount of alcohol is unchanged after adding water. So, if there are x liters of 18% solution, you have
.18x = .12*10
x = 20/3 L of 18% alcohol, and 10/3 L of water
Or, you can consider that you are reducing the concentration by a factor of 2/3, so you must increase the volume by a factor of 3/2. So, the volume v of 18% alcohol can be found by
3/2 v = 10
v = 20/3
A pharmacist has an 18% alcohol solution. How much of this solution and how much water must be mixed together to make 10 liters of a 12% alcohol solution?
1 answer