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One number is two less than a second number. If you take one-half of the first number and increase in by the second number, the result is at least 41. Find the least possible value for the second number.

HELP PLEASE!!!! I hate word problems!!!

1 answer

1st#=x-2
2nd#=x

1/2(x-2)+x=41
x-2+2x=82
3x=84
x=28
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