One number is 10 less than twice a second number.Find a pair of such numbers so that their product is as small as possible.

Question

x-10
2x

2x(x-10)
2x^2-20x

-(-20/2(2))=5

2(5)^2-20(5)
50-100=-50

I think I am really lost

Answer 1

I agree you are lost.
one number=secondnumber-10
product=onenumber*(seconnumber )
product=(seconnumber-10)(secondnumber)
= Second^2-10Second
taking derivitives..
dProduct/dS=2S-10 set to zero
Second number=5
first number=15

Answer 2

I tried those answer previously and they are incorrect

Answer 3

by small, do you mean in absolute value? If so, then since

2*5-10 = 0,
5 and 0 will have a product of zero.

Otherwise, x(2x-10) has a minimum value of -12.5 when x = 2.5