Asked by Shelbee
a rectangle has the length twice the side of this square and width three units less than the side of this square. if the two areas are equal, what are the squares dimensions (w * h)?
Answers
Answered by
Steve
(2s)(s-3) = s^2
2s^2 - 6s = s^2
s^2 - 6s = 0
s(s-6) = 0
s=6
so, the square is 6x6
check: 12*3 = 36 = 6^2
2s^2 - 6s = s^2
s^2 - 6s = 0
s(s-6) = 0
s=6
so, the square is 6x6
check: 12*3 = 36 = 6^2
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