The balanced equation for the reaction is:
I2 + 2NaCl -> 2NaI + Cl2
From the equation, we can see that there are 4 atoms in the products: 2 sodium (Na) atoms and 2 iodine (I) atoms.
Therefore, the correct answer is option d) 4.
One molecule of Iodine (I2) and two molecules of sodium chloride (NaCl) combine in a reaction. How many atoms are in the products?
a
3
b
2
c
6
d
4
1 answer