by Pythagoras
10^2 + x^2 = (20 + x)^2
x^2 + 100 = x^2 + 40x + 400
-300 = 40 x
there appears to be something wrong with the numbers in the problem
one leg of the right triangle is 10 cm and the hypotenuse is 20 cm longer than the other leg.Find the lenght of the unknown sides.
1 answer