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One leg of a right triangle is 3cm more than half the length of the other leg.the area of the triangle is 54cm^2. How long are each of the legs.

2 answers

first leg = x
second leg = x/2 plus 3

area of a triangle is 1/2 times bh

54 = 1/2 times ((x) times ( x/2 + 3))

Can you finish from here?

No ...im so lost

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