One enzyme- catalyzed reaction in a biochemical cycle has an equilibrium constant (K1) that is 10 times the equilibrium constant (K2) of a second reaction. If the standard Gibbs energy of the former reaction is - 300 kJ mol-1, what is the standard reaction Gibbs energy of the second reaction?

Answer 1

There may be an easier way to do it but I would use dGo = -RTlnK and solve for K. Multiply that K by 10 and recalculate dGo.

Answer 2

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