Asked by Munavvar
At body temperature (37C), K of an enzyme-catalyzed reaction is 2.3x10^14 times greater than k of the uncatalyzed reaction. Assuming that the frequency factor A is the same for both reaction, by how much does the enzyme the E^a?
Answers
Answered by
DrBob222
ln 2.3E14 = -Ea/RT
Solve for Ea
Solve for Ea
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