The diameter of the circle is 12 cm.
The quadrilateral consists of two congruent triangles, with base 12 and altitude 4. So, its area is 48 cm^2
one diagonal of a cyclic quadrilateral coincides with a diameter of a circle whose area is 36pi cm^2. If the other diagonal which measures 8cm meets the first diagonal at right angles, find the area of quadrilateral. Show your solutions
2 answers
How did you got your answer. I need a complete solution please.