Our club elections are tomorrow. How many different ways can president, vice
president, secretary and treasurer been chosen from 8 students? (D1b)
a) 8 b) 70 c) 1680 d) 4096
One card is selected at random from an ordinary set of 52
cards. Find the probability of each of the following events:
b. A spade and a 5 are drawn.
d. A jack is not drawn.
3 answers
b) so you are picking the 5 of spades
so prob(5 of spades) = 1/52
d) prob (of a jack) = 4/52 = 1/13
then prob(not a jack) = 1 - 1/13 = 12/13
so prob(5 of spades) = 1/52
d) prob (of a jack) = 4/52 = 1/13
then prob(not a jack) = 1 - 1/13 = 12/13
Please post your question in a new post, not as a reply to somebody else's.
There are 8 ways to pick a president, then 7 ways to pick a vp, then 6 ways for the treasurer , and 5 ways for the secretary.
So the number of ways = 8x7x6x5 = 1680
There are 8 ways to pick a president, then 7 ways to pick a vp, then 6 ways for the treasurer , and 5 ways for the secretary.
So the number of ways = 8x7x6x5 = 1680