Magnitude of displacement (vector)
=290m
velocity=2.0m/s
(a)
Walking time = distance /speed
= 290m / 2.0m/s
= 145s
(b)
Northerly distance
= 290cos(25°)
= 262.8m
Westerly distance
= 290sin(25°)
= 122.6m
Total distance
= 385.4m
Average speed
= 385.4m / 145s
= 2.66 m/s
On the way to class, you walk north and then west such that your resultant displacement is 290 m in a direction 25deg west of north. Your average velocity is 2.0 m/s in the same direction as the displacement.
Calculate (a) your walking time and (b) your average speed.
1 answer
1 answer