A man in search of his dog drives first 13.3 mi northeast, then 17.3 mi straight south, and finally 6.85 mi in a direction 30.3° north of west.

a) What is the magnitude of his resultant displacement?



b) What is the direction of his resultant displacement? Express your answer counterclockwise relative to the positive x-axis.

1 answer

Here are the formulas that'll lead you to the answer. Just do the math to solve for the horizontal and vertical, then plug and chug.

A)
Horizontal = 13.3cos45 + 0 - 6.85cos30.3
Vertical = 13.3sin45 - 17.3 + 6.85sin30.3

(Vertical)^2 + (Horizontal)^2 = (Overall Displacement)^2
Root(Vertical^2 + Horizontal^2) = Magnitude of Displacement

B)
Angle = Tan(Vertical/Horizontal)