On another planet, the isotopes of titanium have the following natural abundances.
Isotope 46Ti Abundance 70.900% Mass(amu) 45.95263
Isotope 48Ti Abundance 10.000% Mass(amu) 47.94795
Isotope 50Ti Abundance 19.100% Mass(amu) 49.94479
What is the average atomic mass of titanium on that planet?
I got 46.9 amu but it is wrong.
11 answers
(45.95263*0.7090) + (47.94795*0.10) + (49.9479*0.191) = ?
15.64
i have no idea
You forgot your significant figures.
46.70 amu
.70900 x 45.95263 = 32.580
.10000 x 49.94479 = 4.7948
.19100 x 49.94479 = 9.5395
*(Be aware that these answers must have 5 significant figures)
32.580 + 4.7948 + 9.5395 = 46.918
*(Be aware that the final answer must go to 3 decimal places)
.10000 x 49.94479 = 4.7948
.19100 x 49.94479 = 9.5395
*(Be aware that these answers must have 5 significant figures)
32.580 + 4.7948 + 9.5395 = 46.918
*(Be aware that the final answer must go to 3 decimal places)
46.83
Remember that while calculating you are not suppose to approximate not until you arrive at your final answer.
Remember that while calculating you are not suppose to approximate not until you arrive at your final answer.
I'm sorry I posted the right answer to the wrong question
46.713 you welcomw
It’s 46.811 u
46.627 u is the correct answer
There are three isotopes of titanium present, 46Ti, 48Ti, and 50Ti, so there are three terms in the weighted average equation.
average atomic mass=(45.95263 u×74.500%100%)+(47.94795 u×17.200%100%)
+(49.94479 u×8.300%100%)
average atomic mass=46.627 u
There are three isotopes of titanium present, 46Ti, 48Ti, and 50Ti, so there are three terms in the weighted average equation.
average atomic mass=(45.95263 u×74.500%100%)+(47.94795 u×17.200%100%)
+(49.94479 u×8.300%100%)
average atomic mass=46.627 u