initial KE=workdoneonfriction+finalKE
1/2 m vi^2=mu*mg*distance+0
distance=1/2 vi^2/g
On a frozen pond, a 13.9 kg sled is given a kick that imparts to it an initial speed of v0 = 1.81 m/s. The coefficient of kinetic friction between sled and ice is μk = 0.122. Use the work kinetic energy theorem to find the distance the sled moves before coming to rest.
2 answers
call mass m and not 13.9 to save work, it cancels
(1/2) m v^2 = retarding force * d
(1/2)m v^2 = .122 m g d
(1/2)(1.81)^2 = .122(9.81) d
solve for d
(1/2) m v^2 = retarding force * d
(1/2)m v^2 = .122 m g d
(1/2)(1.81)^2 = .122(9.81) d
solve for d