normal force = m g = 98.1
so
friction force = .14*98.1
friction force * d = (1/2) m v^2
.14*9.81 * d = 5 (6.2)^2
solve for d
On a frozen pond, a 10 kg sled is given a kick that imparts to it an initial speed of 6.2 m/s. The coefficient of kinetic friction between sled and ice is 0.14. Find the distance the sled moves before coming to rest. The acceleration of gravity is 9.8 m/s^2.
Answer in units of m.
1 answer
1 answer