On a dry road, a car with good tires may be able to brake with a constant deceleration of 3.31 m/s2. (a) How long does such a car, initially traveling at 28.2 m/s, take to stop? (b) How far does it travel in this time?

Answer 1

0 = 28.2 - 3.31 t

solve for t

then use t

d = 28.2 t - (1/2)(3.31) t^2