time = (delta V)/(acceleration)
= 22.4/4.17 = 5.57 s
distance = time * (avg velocity)
= 5.57*11.2 = 60.2 m
On a dry road, a car with good tires may be able to brake with a constant deceleration of 4.17 m/s2. (a) How long does such a car, initially traveling at 22.4 m/s, take to stop? (b) How far does it travel in this time?
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