you need to add/subtract rows and their multiples so the resulting matrix consists of a diagonal of 1's.
To start, subtract R1 from R2:
x + y + z = -5
0 - 2y + 2z = 4
4x + y + z = -2
Now subtract 4*R1 from R3:
x + y + z = -5
0 - 2y + 2z = 4
0 - 3y - 3z = 18
Now work on the other rows. When the left side is just a diagonal of 1's, the right side will be the solution, because it will look something like
x + 0 + 0 = 12
0 + y + 0 = 4
0 + 0 + z = -3
olve the system of equations using matrices. Use Gaussian elimination with back-substitution.
x + y + z = -5
x - y + 3z = -1
4x + y + z = -2
I need it explained to me, how do I do this?
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