1. agree
2. agree
3. hint f - 4/6 = 5/6 and -f - 4/6 = 5/6
Ok, I am horrible at math so I am going to need someone's help.....
1. Solve.
|x+3|<5
a. -8<x<2 ****
b. -2<x<8
c.3<x<5
d.-3<x<5
2. Solve.
|-3n| - 2 = 4
a. 2 or -2 ****
b. 3 or -3
c. 4 or -4
d. 6 or -6
3. Solve.
|f| - 2/3=5/6
a. 5/6 or -5/6
b. 2/3 or -2/3
c. 1 1/2 or -1 1/2
d. no solution
4. Solve.
-2 |x - 5|≤ -10
a. x ≤ -5 or x ≥ 5
b. -5 ≤ x ≤ 5
c. x ≤ 0 or x ≥ 10
d. -10 ≤ x ≤ 10
5. The ideal circumference of a woman's basketball is 28.75 in. The actual circumference may vary from the ideal by at most 0.25 in. What are the acceptable circumferences for a woman's basketball? Let the variable,c, represent circumference.
a. c ≤ 28.5 in. or c ≥ 29 in.
b. c < 28.5 in. or c > 29 in.
c. 28.5 in. ≤ c ≤ 29 in.
d. 28.5 < c < 29 in.
Please help!!
8 answers
-2 |x - 5|≤ -10
|x-5| >= 5
That is, x must be at least 5 away from 5
x ≤ 0 or x ≥ 10
or, algebraically,
(x-5)^2 >= 25
x^2 - 10x + 25 >= 25
x^2-10x >= 0
x(x-10) >= 0
so, either both are positive (x >= 10)
or both are negative (x <= 0)
28.75 - 0.25 <= c <= 28.75 + 0.25
28.5 <= c <= 29.0
|x-5| >= 5
That is, x must be at least 5 away from 5
x ≤ 0 or x ≥ 10
or, algebraically,
(x-5)^2 >= 25
x^2 - 10x + 25 >= 25
x^2-10x >= 0
x(x-10) >= 0
so, either both are positive (x >= 10)
or both are negative (x <= 0)
28.75 - 0.25 <= c <= 28.75 + 0.25
28.5 <= c <= 29.0
4.
-2 |x - 5|≤ -10
|x-5| >/= 5
ends
(x-5) = 5 is x = 10
-(x-5) = 5 is -x = 0
c
-2 |x - 5|≤ -10
|x-5| >/= 5
ends
(x-5) = 5 is x = 10
-(x-5) = 5 is -x = 0
c
circumference between AND including the end points
Answer:
1: A
2: A
3: C
4: C
5: C
1: A
2: A
3: C
4: C
5: C
playfun is correct i got a 100 !
playfun is 100% correct.
playfun is right, i was on here to check and all the answers were right
3 answers