4NH3 + 3O2----> 2N2 +6H2O
4 mol of NH3=3 mol of O2=2 mol of N2=6 mol of H20
0.23 mol of NH3 *( 3 mol of O2/4 mol of NH3) = # of moles of O2
5 mol of O2 *( 2 mol of N2/3 mol of O2) = # of moles of N2
___NH3+___O2->N2+H2O (this is not balanced)
how many moles of oxygen react with 0.23 moles of NH3?
HOW many moles moles of N2 will be produced when reacted with 5 mol of O2?
1 answer