NaOH + HCl ------> NaCl + HOH

Question

I need to figure out the quantity of heat in this reaction. The volume of the solution is 150 mL (NaCl + HOH). The inital temperature is 26 degrees celcius and the final temperature is 23 degrees celcius. That's all I know. How would I go about figuring this out?

Answer 1

q=m*c*delta T
q is the heat generated, m is the mass (150 g unless you are given some number of density for water other than 1.00 g/mL), and delta T is Tfinal-Tinitial.
Please note the correct spelling of celsius.