Naoh (aq) + HCl (aq) --> NaCl (aq) + H2O (l)

Using the dT determined in part 1, calculate the heat capacity of the calorimeter. Enthalpy of reaction= -58.3 kj/mol, Cs (NaCl = 3.91j/g C)density of 1 M NaCl = 1.037g/mL. dT= 12.88 degrees Celcius.

2 answers

50 mL of 2.00 M HCl and 50 ml of 2.05 M NaOH were used
See your other post below.