Asked by Anonymous
N2H4(g) + H2(g) ---> 2 NH3(g) H1 = –1876 kJ
3 H2(g) + N2(g) ---> 2 NH3(g) H2 = –922 kJ
The H f for the formation of hydrazine: 2 H2(g) + N2(g) N2H4(g) will be _________ kJ/ mol.
3 H2(g) + N2(g) ---> 2 NH3(g) H2 = –922 kJ
The H f for the formation of hydrazine: 2 H2(g) + N2(g) N2H4(g) will be _________ kJ/ mol.
Answers
Answered by
DrBob222
Use Hess' Law.
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