Asked by Cuukoo

N2H4(g) + H2(g) 2 NH3(g) H1 = –1876 kJ

3 H2(g) + N2(g) 2 NH3(g) H2 = –922 kJ

The H f for the formation of hydrazine: 2 H2(g) + N2(g) N2H4(g) will be _____ kJ/mol.
Answered by DrBob222
You can't have an equation without arrows. No arrows means we don't know the reactants from the products.
Answered by brownf0x
95.4 kJ/mol
Answered by kwedge
can you elaborate on how you got that browmf0x?
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