Asked by kendra

N2+2H2=N2H4 What is the concentration of H2 at equalibrium when (N2)=.033 and (N2H2)= .042 M? Keq=5.29
Answered by DrBob222
..........N2 + 2H2 ==> N2H4
aquil..0.033....x......0.042

Keq = (N2H2)/(N2)(H2)^2
Substitute and solve for x.
Answered by kendra
.04905 M
Answered by kendra
0.4905 M
Answered by DrBob222
Yes but if your prof is picky about the number of significant figures s/he may not give you full credit for that answer.
Answered by kendra
ok thanks!
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