N2(g) + H2(g) -> NH3(g) ; how many moles of NH3 is is produced when 0.67 moles of N2 reacts with H2?

Answer 1

N2 + 3H2 ==> 2NH3
Use the coefficients.
0.67 mol N2 x (2 mol NH3/1 mol N2) = 0.67 x (2/1) = ? mol NH3.