N2(g) + 3H2(g) -----> 2NH3(g)
All your answers are right there since the equation is balanced.
for every 6*10^23 molecules of N2 you need 3 * 6*10^23 molecules of H2
In other words 3 mols of H2 for every mol of N2
2. Ammonia is produced by the reaction of hydrogen and nitrogen. N2(g) + 3H2(g) à 2NH3(g)
o a. How many moles of H2 are needed to react with 1.0 mol of N2?
o b. How many moles of N2 reacted if 0.60 mol of NH3 is produced?
o c. How many moles of NH3 are produced when 1.4 mol of H2 reacts?
2 answers
Nitrogen and hydrogren react to produce ammonia.
N2(g) + 3H2(g) --> 2NH3(g)
How many moles of hydrogren are needed to produce 10.0 mol of ammonia?
N2(g) + 3H2(g) --> 2NH3(g)
How many moles of hydrogren are needed to produce 10.0 mol of ammonia?
2 answers