N2(g) + 3H2(g)  2NH3(g) at STP

How many litres of ammonia gas is produced using 5 litres of H2?

5L H2 x (2L NH3 / 3L H2) = 3.33L NH3

How many moles of N2 are needed?

5L H2 x (1L N2 / 3L H2) x (1 mol N2 / 22.41L N2@STP) = 0.0744 mole N2

4 answers

22.4 liters/mol

3.33 L NH3/ (2 Liters NH3/1 liter N2) = 1.67 L N2
1.67 L * 1 mol.22.4 L = .0743 check agree :)
looks good

you might want to be aware of significant figures
thank you!
9. We want to produce 2.75 mol of NH 3 . How many moles of nitrogen would be required N 2 + 3H 2 2NH 3
Similar Questions
  1. N2(g) + 3H2(g)  2NH3(g) at STPHow many litres of ammonia gas is produced using 5 litres of H2? N2 + 3H2 ---> 2NH3 - the ratio
    1. answers icon 4 answers
  2. N2(g) + 3H2(g) -> 2NH3(g) at STPa) How many litres of ammonia gas is produced using 5 litres of H2? b) How many moles of N2 are
    1. answers icon 1 answer
  3. Need Help!1. Ammonia is produced by the reaction of hydrogen and nitrogen. N2(g)+3H2(g)→2NH3(g)ammonia How many moles of N2
    1. answers icon 2 answers
  4. Ammonia is produced by the reaction of hydrogen and nitrogen.N2(g)+3H2(g)→2NH3(g)ammonia How many moles of N2 reacted if
    1. answers icon 1 answer
more similar questions