N2(g) + 3H2(g) -> 2NH3(g) at STP

a) How many litres of ammonia gas is produced using 5 litres of H2?
b) How many moles of N2 are needed?

1 answer

3L H2 produces 2L NH3 -- so 5/3 * 2 = 10/3 L

10/3 L * 1mole/22.4L = 0.15 mole