e^(10-2t)= e^10 * e^-2 t
so
e^10 times transform of e^-2t u(t-5)
My homework question is to find the Laplace transform of the function f(t)=e^(10-2t)*step(t-5).
I am not sure how to handle the e^(10-2t) portion of the equation.
Thanks in advance.
4 answers
then to continue
given f(t) = e^at g(t)
then
F(s) = (1/a) G(s/a)
given f(t) = e^at g(t)
then
F(s) = (1/a) G(s/a)
so....
e^10 (e^-2t) (1/s+5)?
e^10 (e^-2t) (1/s+5)?
or is it:
(e^10)(e^-2t)((e^-5t)/s) = (e^(10-7t))/s?
(e^10)(e^-2t)((e^-5t)/s) = (e^(10-7t))/s?