Multiply the polynomials (3x−1)(2x+4) .(2 points) x2+ x+

Answer 1

To multiply the polynomials \((3x - 1)(2x + 4)\), you can use the distributive property (also known as the FOIL method for binomials). Here’s how it works step by step:

1. First: Multiply the first terms: \[ 3x \cdot 2x = 6x^2 \]

2. Outer: Multiply the outer terms: \[ 3x \cdot 4 = 12x \]

3. Inner: Multiply the inner terms: \[ -1 \cdot 2x = -2x \]

4. Last: Multiply the last terms: \[ -1 \cdot 4 = -4 \]

Now, add all these results together: \[ 6x^2 + 12x - 2x - 4 \]

Combine the like terms (\(12x\) and \(-2x\)): \[ 6x^2 + 10x - 4 \]

So, the product of the polynomials \((3x - 1)(2x + 4)\) is: \[ \boxed{6x^2 + 10x - 4} \]

Answer 2

blankx^2+blankx+blank

Answer 3

The product of the polynomials \((3x - 1)(2x + 4)\) can be expressed in the form \(Ax^2 + Bx + C\).

From the previous multiplication, we found:

\[ 6x^2 + 10x - 4 \]

So in the format \(Ax^2 + Bx + C\):

• \(A = 6\)
• \(B = 10\)
• \(C = -4\)

Therefore, you can fill in the blanks as follows:

• \( \text{blank} = 6 \) (for \(x^2\))
• \( \text{blank} = 10 \) (for \(x\))
• \( \text{blank} = -4 \) (for the constant term)

So, it would look like this:

6x² + 10x - 4