Asked by tinotenda
The polynomials P (x)=x^3-x^2+4x and Q(x)= x^3+6x+10 leave the same remainder when divided by x-a .find the possible values of a and solve the inequality P (x) is greater than Q (x )
Answers
Answered by
Steve
The Remainder Theorem states that the remainder is f(a). So, that means we have
a^3-a^2+4a = a^3+6a+10
a^2+2a+10 = 0
This has no real solutions.
I suspect a typo
As written, P is never greater than Q. See
http://www.wolframalpha.com/input/?i=plot+x%5E3-x%5E2%2B4x+,+x%5E3%2B6x%2B10
a^3-a^2+4a = a^3+6a+10
a^2+2a+10 = 0
This has no real solutions.
I suspect a typo
As written, P is never greater than Q. See
http://www.wolframalpha.com/input/?i=plot+x%5E3-x%5E2%2B4x+,+x%5E3%2B6x%2B10
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.