Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Multiply the polynomial (b+8)(3b−6) to simplify.(1 point) Responses b2+30b−48 b squared plus 30 b minus 48 3b2+18b−48 3 b squar...Question
                Multiply the polynomial  (b+8)(3b−6)  to simplify.(1 point)
Responses
b2+30b−48
b squared plus 30 b minus 48
3b2+18b−48
3 b squared plus 18 b minus 48
3b2+30b−48
3 b squared plus 30 b minus 48
b2+18b−36
b squared plus 18 b minus 36
            
        Responses
b2+30b−48
b squared plus 30 b minus 48
3b2+18b−48
3 b squared plus 18 b minus 48
3b2+30b−48
3 b squared plus 30 b minus 48
b2+18b−36
b squared plus 18 b minus 36
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To multiply the polynomial \((b+8)(3b−6)\), we can use the distributive property (also known as the FOIL method for binomials).
1. Multiply the first terms: \(b \cdot 3b = 3b^2\)
2. Multiply the outer terms: \(b \cdot (-6) = -6b\)
3. Multiply the inner terms: \(8 \cdot 3b = 24b\)
4. Multiply the last terms: \(8 \cdot (-6) = -48\)
Now combine all the terms:
\[
3b^2 + (-6b) + 24b - 48
\]
Combine the like terms:
\[
3b^2 + (24b - 6b) - 48 = 3b^2 + 18b - 48
\]
So, the simplified polynomial is:
\[
3b^2 + 18b - 48
\]
The correct response is:
**3b² + 18b − 48**.
    
1. Multiply the first terms: \(b \cdot 3b = 3b^2\)
2. Multiply the outer terms: \(b \cdot (-6) = -6b\)
3. Multiply the inner terms: \(8 \cdot 3b = 24b\)
4. Multiply the last terms: \(8 \cdot (-6) = -48\)
Now combine all the terms:
\[
3b^2 + (-6b) + 24b - 48
\]
Combine the like terms:
\[
3b^2 + (24b - 6b) - 48 = 3b^2 + 18b - 48
\]
So, the simplified polynomial is:
\[
3b^2 + 18b - 48
\]
The correct response is:
**3b² + 18b − 48**.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.