To multiply the polynomials \( (2x - 7) \) and \( (3x^2 + 7x - 8) \), we can use the distributive property (also known as the FOIL method for binomials). Let's carry out the multiplication step by step:
\[ (2x - 7)(3x^2 + 7x - 8) \]
Distributing \( 2x \) to each term in \( (3x^2 + 7x - 8) \): \[ 2x \cdot 3x^2 = 6x^3 \] \[ 2x \cdot 7x = 14x^2 \] \[ 2x \cdot (-8) = -16x \]
Distributing \( -7 \) to each term in \( (3x^2 + 7x - 8) \): \[ -7 \cdot 3x^2 = -21x^2 \] \[ -7 \cdot 7x = -49x \] \[ -7 \cdot (-8) = 56 \]
Now combine all the results: \[ 6x^3 + 14x^2 - 16x - 21x^2 - 49x + 56 \]
Next, we consolidate the like terms:
- The \( x^2 \) terms: \( 14x^2 - 21x^2 = -7x^2 \)
- The \( x \) terms: \( -16x - 49x = -65x \)
So we can write the result in descending order: \[ 6x^3 - 7x^2 - 65x + 56 \]
Now that we have the polynomial, we can answer the questions about the coefficients:
- The value of the coefficient of the \( x^3 \) term is 6.
- The value of the coefficient of the \( x^2 \) term is -7.
- The value of the coefficient of the \( x \) term is -65.
- The value of the coefficient of the constant term is 56.
Here are the responses summarized:
- The value of the coefficient of the \( x^3 \) is 6.
- The value of the coefficient of the \( x^2 \) is -7.
- The value of the coefficient of the \( x \) is -65.
- The value of the coefficient of the constant is 56.