Multiply the following polynomials and write the resulting polynomial in descending order. 3x−82x2+4x−9. What is the value of the coefficient of the x3term?

To multiply the polynomials \( (3x - 8)(2x^2 + 4x - 9) \), we will distribute each term in the first polynomial to each term in the second polynomial.

Starting with \( 3x \):
1. \( 3x \cdot 2x^2 = 6x^3 \)
2. \( 3x \cdot 4x = 12x^2 \)
3. \( 3x \cdot -9 = -27x \)

Next, we multiply \( -8 \):
1. \( -8 \cdot 2x^2 = -16x^2 \)
2. \( -8 \cdot 4x = -32x \)
3. \( -8 \cdot -9 = 72 \)

Now, we combine all the products:
\[
6x^3 + 12x^2 - 27x - 16x^2 - 32x + 72
\]

Next, we combine like terms:
1. For \( x^3 \): \( 6x^3 \)
2. For \( x^2 \): \( 12x^2 - 16x^2 = -4x^2 \)
3. For \( x \): \( -27x - 32x = -59x \)
4. Constant term: \( 72 \)

Putting it all together, we rewrite the polynomial in descending order:
\[
6x^3 - 4x^2 - 59x + 72
\]

The coefficient of the \( x^3 \) term is \( 6 \).

Thus, the final answer for the coefficient of the \( x^3 \) term is:
\[
\boxed{6}
\]

What is the value of the coefficient of the `x^{2}`term?

From the previous work, we derived the resulting polynomial from the multiplication of the two polynomials \( (3x - 8)(2x^2 + 4x - 9) \):

\[
6x^3 - 4x^2 - 59x + 72
\]

In this polynomial, the coefficient of the \( x^2 \) term is \( -4 \).

Therefore, the value of the coefficient of the \( x^2 \) term is:

\[
\boxed{-4}
\]

What is the value of the coefficient of the x term

From the previously derived polynomial:

\[
6x^3 - 4x^2 - 59x + 72
\]

We can see that the coefficient of the \( x \) term is \( -59 \).

Therefore, the value of the coefficient of the \( x \) term is:

\[
\boxed{-59}
\]

what is the value of the constant

From the previously derived polynomial:

\[
6x^3 - 4x^2 - 59x + 72
\]

The constant term is \( 72 \).

Therefore, the value of the constant is:

\[
\boxed{72}
\]