well, just divide. You will see that (x+3) divides it evenly, and the quotient is -2x^2+5x-2)
so, F(x) = -(x+2)(2x^2-5x+2)
= -(x+3)(x-2)(2x-1)
The zeros can now just be read off.
Consider the following polynomial function
F(x)=-2x^3-x^2+13x-6 to answer the following question.
If (x+3) is a factor of f(x) rewrite f(x) in completely factored form and identify the zeros f(x).
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