To multiply the polynomials \( (3x - 8)(2x^2 + 4x - 9) \), we'll use the distributive property (FOIL method) to find the product.
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Multiply \(3x\) by each term in the second polynomial:
- \(3x \cdot 2x^2 = 6x^3\)
- \(3x \cdot 4x = 12x^2\)
- \(3x \cdot (-9) = -27x\)
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Multiply \(-8\) by each term in the second polynomial:
- \(-8 \cdot 2x^2 = -16x^2\)
- \(-8 \cdot 4x = -32x\)
- \(-8 \cdot (-9) = 72\)
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Combine all the terms together: \[ 6x^3 + 12x^2 - 27x - 16x^2 - 32x + 72 \]
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Combine like terms:
- For \(x^2\): \(12x^2 - 16x^2 = -4x^2\)
- For \(x\): \(-27x - 32x = -59x\)
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Write the resulting polynomial in descending order: \[ 6x^3 - 4x^2 - 59x + 72 \]
Now, we can identify the coefficients:
- The coefficient of the \(x^3\) term is 6.
- The coefficient of the \(x^2\) term is -4.
- The coefficient of the \(x\) term is -59.
- The constant term is 72.
Final answers:
- The value of the coefficient of the \(x^3\) term is 6.
- The value of the coefficient of the \(x^2\) term is -4.
- The value of the coefficient of the \(x\) term is -59.
- The value of the constant is 72.