Mr Leon spent $60 on some apples, mangoes and pears in the ratio 3:5:2. The number of apples was twice the number of mangoes. The number of pears was 1/3 the number of apples. The mangoes were at 3 for $5. How many fruits did he buy altogether?

Answer 1

The cost of the x mangoes is 5/3 x so the costs are in the ratio
5x : 5/3 x : 10/3 x
5x + 5/3 x + 10/3 x = 60
x = 6

If there were a,m,p of each fruit, respectively, then
a = 2m
3a = p
so a:m:p = 2:1:6
now, knowing there were 6 mangoes, we have
12+6+36 = 54 fruits

Answer 2

amount spent on apples --- $ 3x
amount spent on mangoes -- $ 5x
amount spent on pears ---$ 2x
3x+5x+2x = 60
x = 6

"The mangoes were at 3 for $5", but he spent 5x or $30 on mangoes
at 3 for $5, there must have been 18 mangoes.

number of
apples : pears : mangoes = 2y : 2y/3 : y
= 6y : 2y : 3y

But we know the number of mangoes is 18
so 3y = 18, y = 6
so we have 36 apples, 12 pears and 18 mangoes

check:
twice as many apples as mangoes ?? Yes
The number of pears was 1/3 the number of apples ?? , YES

I think oobleck has the number of apples as 1/3 the number of pears, should be the other way around.