Morgan owns a car dealership in which her employees earn commission for each car they sell in addition to a weekly salary. One employee sells 5 cars and makes $1,875 that week. A second employee sells 6 cars and makes $2,150 that week.

Enter an equation, in slope-intercept form, for the amount of money y
an employee will make in a week given the number of cars sold x
.

3 answers

To find the equation in slope-intercept form \( y = mx + b \), where \( y \) represents the total earnings, \( x \) represents the number of cars sold, \( m \) is the slope (the commission earned per car sold), and \( b \) is the weekly salary.

Let's denote:

  • \( y_1 = 1875 \) when \( x_1 = 5 \) (for the first employee)
  • \( y_2 = 2150 \) when \( x_2 = 6 \) (for the second employee)

We can set up a system of equations based on the given information:

  1. \( 1,875 = m \cdot 5 + b \)
  2. \( 2,150 = m \cdot 6 + b \)

To solve these equations, we can start by eliminating \( b \):

From the first equation: \[ b = 1875 - 5m \]

Now, substitute \( b \) into the second equation: \[ 2150 = 6m + (1875 - 5m) \]

This simplifies to: \[ 2150 = 6m + 1875 - 5m \] \[ 2150 = m + 1875 \] \[ m = 2150 - 1875 = 275 \]

Now that we have the value of \( m \), we can substitute it back to find \( b \): \[ b = 1875 - 5 \cdot 275 \] \[ b = 1875 - 1375 = 500 \]

Now, we have \( m = 275 \) and \( b = 500 \). The equation in slope-intercept form is: \[ y = 275x + 500 \]

Therefore, the equation representing the earnings of an employee based on the number of cars sold is: \[ \boxed{y = 275x + 500} \]

How much will an employee earn for selling 10 cars in one week? Enter the answer.

To find out how much an employee will earn for selling 10 cars in one week, we can use the equation we derived earlier:

\[ y = 275x + 500 \]

where \( x \) is the number of cars sold. We will substitute \( x = 10 \) into the equation:

\[ y = 275(10) + 500 \] \[ y = 2750 + 500 \] \[ y = 3250 \]

Therefore, an employee will earn $3,250 for selling 10 cars in one week.